A radiation of energy $'E'$ falls normally on a perfectly reflecting surface. The momentum transferred to the surface is $( C =$ Velocity of light $)$
$\frac{E}{{C\;}}$
$\;\frac{{2E}}{C}$
$\;\frac{{2E}}{{{C^2}}}$
$\;\frac{E}{{{C^2}}}$
In a photo cell, the photo-electrons emission takes place
In a photoelectric effect experiment a light of frequency $1.5$ times the threshold frequency is made to fall on the surface of photosensitive material. Now if the frequency is halved and intensity is doubled, the number of photo electrons emitted will be:
In photo electric effect
$A.$ The photocurrent is proportional to the intensity of the incident radiation.
$B.$ Maximum Kinetic energy with which photoelectrons are emitted depends on the intensity of incident light.
$C.$ Max. $K.E$ with which photoelectrons are emitted depends on the frequency of incident light.
$D.$ The emission of photoelectrons require a minimum threshold intensity of incident radiation.
$E.$ Max. K.E of the photoelectrons is independent of the frequency of the incident light.
Choose the correct answer from the options given below:
For photo-electric effect with incident photon wavelength $\lambda$, the stopping potential is $V _0$. Identify the correct variation$(s)$ of $V _0$ with $\lambda$ and $1 / \lambda$. $Image$